6u^2+36u=0

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Solution for 6u^2+36u=0 equation: 



6u^2+36u=0

a = 6; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·6·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$


$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*6}=\frac{-72}{12}
=-6
$


$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*6}=\frac{0}{12}
=0
$

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